Answer:
21.75 km/h
Step-by-step explanation:
Let's call the aircraft carrier speed 'x', so the speed of the container ship is 'x+8'
The distance travelled can be found with the product of the speed and the time travelled: d = v * t
The aircraft carrier travelled five hours, so the distance travelled is:
d1 = x * 5 = 5x
Then, the container ship travelled seven hours, so the distance travelled is:
d2 = (x+8)*7 = 7x + 42
As they travelled in opposite directions, the distance between then is the sum of these distances, and it is equal 303 km, so we have that:
d1 + d2 = 303
5x + 7x + 42 = 303
12x = 261
x = 21.75 km/h
Answer:
The aircraft carrier's speed was 13 km/h
Step-by-step explanation:
The parameters given in the question are;
Time of departure of the aircraft carrier = 5 hours before the container ship
Speed of the container ship = 8 km/h faster than the aircraft carrier
Distance between the two ships after 7 hours = 303 km
Let the speed of the aircraft carrier be Z
∴ The speed of the container ship = Z + 8
Since the aircraft carrier left port 35 travelling North 5 hours earlier we have;
Total time of travel of the aircraft carrier at the time of measurement of the distance between the two ships = 5 + 7 = 12 hours
Therefore, since both ships are moving in opposite direction on the same line path, we have;
303 = 12×Z + 7 × (Z + 8) = 12·Z + 7·Z + 56
19·Z = 303 - 56 = 247
∴ Z = 247/19 = 13 km/h
Hence, the aircraft carrier's speed was 13 km/h.
