Question

Approximate the real zeros of /(x) = x2 + 3x + 2 to the nearest tenth.
2.1
b.
1.0
-2.-1
a.
0.-1
d.

Answer 1

Answer:

x = - 2, x = - 1

Step-by-step explanation:

Given

f(x) = x² + 3x + 2

To find the zeros let f(x) = 0, that is

x² + 3x + 2 = 0

Consider the factors of the constant term (+ 2) which sum to give the coefficient of the x- term (+ 3)

The factors are + 2 and + 1, since

2 × 1 = 2 and 2 + 1 = 3, thus

(x + 2)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x + 1 = 0 ⇒ x = - 1

Answer 2

Answer:

Real Zeros: -1, -2

Step-by-step explanation:

$x^{2} +3x+2=0$

Plug into quadratic equation formula:

$\frac{-3+\sqrt{3^{2}-4ac} }{2(1)}= -1 \\\frac{-3-\sqrt{3^{2}-4ac} }{2(1)}= -2$

Hope this helped!