Question

What is the solution to In (x2 - 16) = 0?
x=1v17
x= +4
x=+/32

Answer 1

Answer:

x = ± $\sqrt{17}$

Step-by-step explanation:

Given

ln(x² - 16) = 0, then

x² - 16 = $e^{0}$ = 1 ( add 16 to both sides )

x² = 17 ( take the square root of both sides )

x = ± $\sqrt{17}$

Answer 2

Answer:

B.

Step-by-step explanation:

x²-16 = 0

Adding 16 to both sides

x² = 16

Taking square root on both sides

we get

√x² = √16

x = ± 4

Either,

x=4        OR             x= -4