Answer:
Check the explanation
Explanation:
given
charge of [tex]1.11 * 10^{-10}[/tex] C
radius 250m
The potential at a point 1m
and 1 V
mass 2 micrograms
charge of +2 Coulombs
the potential is V = K Q / r
V = 9 X 109 X 1.11 X 10-10 / 1
V = 9 X 109 X 1.11 X 10-10
V = 0.999 volt
nearly it is V = 1 v
the energy stored is U = q X V
U = 2 X 1
U = 2 J
the energy is stored in this configuration is U = 2 J