Answer:
The concentration of NaOH is 2.47 M
Explanation:
The equation of the reaction is
HCl (aq) + NaOH(aq) ------> NaCl(aq) + H2O(l)
Given;
Concentration of acid CA= 1.25 M
Volume of acid VA= 5.0L
Concentration of base CB= ????
Volume of base VB= 2.53 L
Number of moles of acid NA= 1
Number of moles of base NB= 1
From;
CAVA/CBVB= NA/NB
CAVANB= CBVBNA
CB= CAVANB/VBNA
CB= 1.25 × 5.0 ×1 / 2.53×1
CB= 2.47 M
Therefore the concentration of NaOH is 2.47 M
