Question

What is the volume of a hemisphere with a radius of 61.9 m, rounded to the nearest
tenth of a cubic meter?

Answer 1

Answer:

The volume of the hemisphere is 496741.6 m³

Step-by-step explanation:

The volume of an sphere is given by:

$V_{s} = \frac{4\pi r^{3}}{3}$

In which $\pi = 3.14$ and r is the radius.

An hemisphere is half of an sphere, so it's volume is half the sphere's volume. So

$V_{h} = \frac{V_{s}}{2} = \frac{2\pi r^{3}}{3}$

In this question:

$r = 61.9$. So

$V_{h} = \frac{2\pi (61.9)^{3}}{3} = 496741.6$

The volume of the hemisphere is 496741.6 m³

Answer 2

Answer:

The volume of the hemisphere = 496741.6 m³

Step-by-step explanation:

Volume of a sphere is= (4/3) × π × r³

r is the radius

π is 22/7

hemisphere is half of an sphere,

so the volume of henisphere is  (2/3) × π × r³

Given that ;

r = 61.9 m

$V = \frac{2\pi (61.9)^{3}}{3} = 496741.6$

therefore, the volume of the hemisphere is 496741.6 m³