A hydraulic press has a large circular piston of radius 0.8m and circular plunger of radius 0.1m . A force of 200N is exerted by a plunger . Find the force exerted on the piston

Respuesta :

Answer:

[tex]F_{o}=12800 N[/tex]  

Explanation:

Let's use the Pascal principle:

[tex]P_{i}=P_{o}[/tex]

[tex]\frac{F_{i}}{A_{i}}=\frac{F_{o}}{A_{o}}[/tex]

Where:

F(i) is the input force, 200 N

F(o) is force exerted on the piston  

A(i) is the area of the plunger (A =πr(i)²)

A(o) is the area of the piston (A =πr(o)²)

[tex]F_{o}=\frac{A_{o}F_{i}}{A_{i}}[/tex]

[tex]F_{o}=\frac{r_{o}^{2}F_{i}}{r_{i}^{2}}[/tex]

[tex]F_{o}=\frac{0.8^{2}*200}{0.1^{2}}[/tex]                

[tex]F_{o}=12800 N[/tex]              

I hope it helps you!                    

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