Answer:
Y = 4/3x + 0
Step-by-step explanation:
(-3,-4) and (3,4) can be plugged in to rise over run.
y 4 -(-4) = 8
x 3 - (-3) = 6
8/6 = 4/3
Plug into slope intercept form
4 = 4/3(3) + b
4 = 12/3 +b
4 = 4 +b
Subtract from both sides
0 = b
Y = 4/3x + 0
The equation in slope intercept form that goes through the points (-3,-4) and (3,4) is [tex]y=\frac{8}{6}x[/tex]
The slope of a line gives the measure of its steepness and direction.
The equation of a straight line in the form y = mx + b where m is the slope of the line and b is its y-intercept.
Given,
Slope of the line passing through the points (-3,-4) and (3,4)
Slope of the line m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1}}=\frac{4+4}{3+3}=\frac{8}{6}[/tex]
Therefore slope of the line is [tex]\frac{8}{6}[/tex]
Find the y intercept using the slope and the point (-3,-4)
y=mx + b
-4 = [tex]\frac{8}{6}[/tex]×-3 + b
-4 =-4+b
b=-4+4 =0
Then,
The equation in slope intercept form is
y = mx + b
y = [tex]\frac{8}{6}[/tex]x + 0
[tex]y=\frac{8}{6}x[/tex]
Hence, the equation in slope intercept form that goes through the points (-3,-4) and (3,4) is [tex]y=\frac{8}{6}x[/tex]
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