Question

For the equation 3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O, how many units of NO3 are represented on the products side?
A 2
B 3
C 6
D 8

Answer 1

Answer:

C

Explanation:

Answer 2

Following are the calculation to units of $\bold{NO_{3}}$:

Given equation:

$\bold{3Cu + 8HNO_3 \longrightarrow 3Cu(NO_3)2 + 2NO + 4H_2O}$

To find:

units of $\bold{NO_{3}}$=?

Solution:

$\bold{3Cu + 8HNO_3 \longrightarrow 3Cu(NO_3)2 + 2NO + 4H_2O}$

• The above-given equation when the 3 mol copper reacts with Nitric acid so, it will give 3 mol Cupric nitrate, 2 mol nitric oxide, and 4 mol of water.
• In the above-given equation$\bold{3Cu(NO_3)_2= 3Cu +3(NO_3)_2 =3Cu +6(NO_3) }$ there are 6 mols of$\bold{NO_3}$.

Therefore, the final answer is "Option C".

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