Answer:
a) 75.4 kg
b) [tex]h(W)=\frac{W+83}{2.2}[/tex]
Step-by-step explanation:
a) The ideal weight of a 6-foot (72 inches) male is given by simply applying h= 72 in to the expression:
[tex]W(72) = 49+2.2(72-60)\\W(72) =75.4\ kg[/tex]
b) Expressing height as a function of weight:
[tex]W(h)= 49+2.2(h-60)\\2.2h-132+49=W\\h(W)=\frac{W+83}{2.2}[/tex]
Verifying with W(h(W)):
[tex]W(h(W))= 49+2.2(\frac{W+83}{2.2} -60)\\W(h(W))= 49-132+W+83\\W(h(W))=W[/tex]
Verifying with h(W(h):
[tex]h(W(h))=\frac{(49+2.2(h-60))+83}{2.2}\\h(W(h))=\frac{(49+2.2h-132+83)}{2.2}\\h(W(h))=h[/tex]