Question

−2z+10+7z=16z+7
How many solutions does the following equation have?

Answer 1

-2z+10+7z = 16z+7

Simplify the left side:

5z+10 = 16z +7

Subtract 5z from both sides:

10 = 11z + 7

Subtract 7 from both sides:

3 = 11z

Divide both sides by 11

Z = 3/11

There is only one solution, which is z= 3/11

Answer 2

Steps to solve:

−2z + 10 + 7z = 16z + 7

~Combine like terms

(-2z + 7z) + 10 = 16z + 7

~Simplify

5z + 10 = 16z + 7

~Subtract 16z to both sides

5z - 16z + 10 = 16z - 16z + 7

~Simplify

-11z + 10 = 7

~Subtract 10 to both sides

-11z + 10 - 10 = 7 - 10

~Simplify

-11z = -3

~Divide -11 to both sides

-11z/-11 = -3/-11

~Simplify

z = 3/11

Best of Luck!