Question

What the oxidation state of sulfur in sulfite?

Answer 1

Answer:

+4

Explanation:

$SO^{-2} _{3}$ , Oxygen always works with -2. You multiply with the number of atoms -2*3= -6

S=x+(-6)=-2

x-6=-2   -> x= -2+6  -> x= +4

Answer 2

+4 is the answer I got it right hope this helps