Answer:
If the temperature was increased to 404 K, its volume would be 3.68 L.
Explanation:
Charles' Law gives a relationship between the volume and the temperature of the gas at constant temperature. This law states that the volume of a given amount of gas held at constant pressure is directly proportional to the temperature.
[tex]V\propto T[/tex]
[tex]\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}[/tex]
Let
[tex]V_1=2.76\ L\\\\T_1=303\ K\\\\T_2=404\ K[/tex]
Let [tex]V_2[/tex] is new volume. Using above formula we get :
[tex]V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{2.76\times 404}{303}\\\\V_2=3.68\ L[/tex]
If the temperature was increased to 404 K, its volume would be 3.68 L.