Question

Which are the solutions of x2 = –13x – 4?
dont gime bs just answer it
85 points btw

Answer 1

Step-by-step explanation:

Step 1:  Add 13x to both sides

$x^2 + 13x = -13x + 13x - 4$

$x^2 + 13x = -4$

Step 2:  Add 4 to both sides

$x^2 + 13x + 4 = -4 + 4$

$x^2 + 13x + 4$

Step 3:  Use Quadratic Formula

$x = \frac{ -b \pm \sqrt{ b^2 - 4ac } }{2a}$

$x = \frac{ -(13) \pm \sqrt{ 13^2 - 4(1)(4)} } { 2(1)}$

$x = \frac{-13 \pm \sqrt{153}}{2}$

$x = \frac{-13\pm3\sqrt{17} }{2}$

Answer:  $x = \frac{-13\pm3\sqrt{17} }{2}$

Answer 2

Answer:

-0.3 and - 12.7

Step-by-step explanation:

Rewrite in quadratic form:

x2 + 13x + 4 = 0

The best approximations, given the options, are 0 and - 13

The actual solution is -