Answer:
[tex] Range =1.41-0.66 = 0.75[/tex]
[tex] \bar X = 1.171 W/Kg[/tex]
[tex] s^2 = 0.0607[/tex]
And taking the square root we got the sample deviation:
[tex] s = \sqrt{0.0607}= 0.246 W/kg[/tex]
Step-by-step explanation:
For this case we have the following datset given:
0.83 1.39 1.39 1.03 0.66 1.26 1.39 1.18 1.41 1.19 1.15
We need to find the range, and the range is defined by:
[tex] Range = Max -Min[/tex]
And replacinng we got:
[tex] Range =1.41-0.66 = 0.75[/tex]
Then we can find the sample variance, but firt we need to find the sample mean with this formula:
[tex]\bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]
And replacing we got:
[tex] \bar X = 1.171 W/Kg[/tex]
Now we can find the sample variance with this formula:
[tex] s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}[/tex]
And replacing we got:
[tex] s^2 = 0.0607[/tex]
And taking the square root we got the sample deviation:
[tex] s = \sqrt{0.0607}= 0.246 W/kg[/tex]