The probability Kalya rolls an even number on the red cube and a multiple of [tex]3[/tex] on the blue cube is [tex]16%[/tex] percent, when both the cubes have faces labeled [tex]1[/tex] through [tex]6[/tex].
The ratio of the favourable number of outcomes to the total number of outcomes is known as Probablity.
First, find the possible outcomes.
Kalya has a red number cube and a blue number cube. Each number cube has faces labeled [tex]1[/tex] through [tex]6[/tex].
So, possible outcomes [tex]=(6[/tex]×[tex]6)=36[/tex]
Let, [tex]S[/tex] be the sample space.
Then, [tex]n(S)=36[/tex]
Let, [tex]E=[/tex]the event of getting an even number on the red cube and a multiple of [tex]3[/tex] on the blue cube.
[tex]E=(2,3),(2,6),(4,3),(4,6),(6,3),(6,6)[/tex]
Then, [tex]n(E)=6[/tex]
Let, [tex]P[/tex] is the probability of the event [tex]E[/tex].
So, [tex]P(E)=\frac{n(E)}{n(S)}=\frac{6}{36}=\frac{1}{6}[/tex]≈[tex]16[/tex] percent
Thus, the probability Kalya rolls an even number on the red cube and a multiple of [tex]3[/tex] on the blue cube is [tex]16[/tex] percent.
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