Question

what temperature in kelvin does 21 of sulfur dioxide occupy if there are 2.5 mol of it at 1.75 atm?

Answer 1

Answer: 179 K

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 1.75 atm

V = Volume of gas = 21 L

n = number of moles = 2.5

R = gas constant =$0.0821Latm/Kmol$

T = temperature in Kelvin = ?

$T=\frac{PV}{nR}$

Putting the values , we get :

$T=\frac{1.75atm\times 21L}{2.5\times 0.0820 L atm/K mol}=179K$

Thus temperature in kelvin is 179 for 21 L of sulfur dioxide occupy if there are 2.5 mol of it at 1.75 atm