Answer:5 and 3
So we let the number take the letter b, anc the expression of the question is:
b^2+15=8×b.....so
b^2+15=8b
Then we take the 8b to the other side of the equal sign so that it becomes...
b^2+15-8b=0
Hence it becomes a quadatic equation following the principle ax^2+bx+c where x is the unknown...
From there we work out to get two different numbers...either b-5=0
b=5
Or b-3=0
b=3
So the two numbers are 5 and 3
