What’s the correct answer for this?
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The square root of 10 is a number with the following property: when you square it, you get 10.
So, if we have [tex]a<\sqrt{10}<b[/tex], where [tex]a[/tex] and [tex]b[/tex] are positive integers, if we square the whole inequality we have
[tex]a^2<10<b^2[/tex]
Let's analyse option A for example. Given everything we said so far, we would have
[tex]1<\sqrt{10}<2 \iff 1^2<10<2^2 \iff 1<10<4[/tex]
which is false.
Option B is again false, because we would have
[tex]2<\sqrt{10}<3 \iff 2^2<10<3^2 \iff 4<10<9[/tex]
which is again false. Keep trying with options C and D following those same steps, and see which one is correct
Answer:
C
Step-by-step explanation:
√10=3.16
3.16 is between 3 and 4 hence C is the answer