Respuesta :
The difference between the two given fractions is [tex]\frac{x^2 + 4x - 1}{x^2 + 2x}[/tex].
The given parameters:
[tex]\frac{x + 5}{x + 2} - \frac{x+ 1}{x^2 + 2x}[/tex]
The difference between the two fractions is calculated as follows;
[tex]\frac{x + 5}{x + 2} - \frac{x+ 1}{x^2 + 2x}\\\\= \frac{x + 5}{x + 2} - \frac{x+ 1}{x(x + 2)}\\\\[/tex]
The lowest common multiple (L.C.M) of the two denominators = x(x + 2)
[tex]= \frac{x(x + 5) - (x + 1)}{x(x + 2)} \\\\= \frac{x^2 + 5x - x - 1}{x^2 + 2x} \\\\= \frac{x^2 + 4x - 1}{x^2 + 2x}[/tex]
Thus, the difference between the two given fractions is [tex]\frac{x^2 + 4x - 1}{x^2 + 2x}[/tex].
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