Question

What is the force applied to a charge if a charge of 0.86 C is moved through an electronic field with a strength of 1,739.90 N/C

Answer 1

Answer:

Force, F = 1496.31 N

Explanation:

We have,

Charge, Q = 0.86 C

Electric field, E = 1739.90 N/C

It is required to find the force applied to a charge. When an object is placed in the electric field, it will posses electric force. The electric force acting on the charge is given by :

$F=qE$

$F=0.86\ C\times 1739.90\ N/C\\\\F=1496.31\ N$

So, the force applied to the charge is 1496.31 N.