Question

A woman is pushing a 38.7kg lawnmower initially at rest with a 68.7N forward force against friction. The lawnmower speeds up to 1.44m/s in 3.81s. How much force does friction evert on the mower

Answer 1

Answer:

expected acceleration= 68.7/38.7=1.77 m/s^2

witnessed acceleration = 1.44/3.81 = 0.37 m/s^2

difference = 1.4m/s^2

so friction = 38.7× 1.4= 54.18 N

Answer 2

Answer:

54.18

Explanation:

54.18 works for acellus