Question

One number is 8 times a first number. a third number is 100 more than the first number. If the sum of the three numbers is 420, find the numbers

Answer 1

Answer:

(use algebra) 1st no. is a,2nd no. is 8 times the 1st which is 8a, 3rd no. 100 more than 1st which is a+100

total is 420, thus a+8a+a+100=420

10a+100=420, take 100 to the other side

10a=320 hence 32

1st no. is 32, 2nd is 256, 3rd is 356