Respuesta :
Answer:
[tex]\frac{13+\sqrt{29}}{10} , \frac{13-\sqrt{29}}{10}[/tex]
Step-by-step explanation:
[tex]5x^2-13x+7=0[/tex]
[tex]x=\dfrac{13\pm \sqrt{169-140}}{10}=\frac{13+\sqrt{29}}{10} , \frac{13-\sqrt{29}}{10}[/tex] . Hope this helps!
Answer:
[tex]\frac{13+\sqrt{29}}{10} , \frac{13-\sqrt{29}}{10}[/tex]
Step-by-step explanation:
Verified correct with K12 test.
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