Answer: 331 K
Explanation:
To calculate the temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1\text{ and }T_1[/tex] are the initial pressure and temperature of the gas.
[tex]P_2\text{ and }T_2[/tex] are the final pressure and temperature of the gas.
We are given:
[tex]P_1=12.5psi\\T_1=?\\P_2=10.5psi\\T_2=5^0C=(5+273)K=278K[/tex]
Putting values in above equation, we get:
[tex]\frac{12.5}{T_1}=\frac{10.5}{278}\\\\T_1=331K[/tex]
Hence, the temperature at which the balls inflated to explain this pressure drop is 331 K