Respuesta :
Answer:
Q= 29.2 J
Explanation:
22°C=295K
37°C=310K
Q= mC dT
Q= (15.0 g) *(0.130 J/g-K)* (310 K-295K)
Q= 29.2 J
29.2 J is required to raise the temperature of 15.0 g of lead from 22.0 °C to 37.0 °C.
What is specific heat capacity?
The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).
Given data:
22°C=295K
37°C=310K
Applying specific heat capacity formula:
Q= mC dT
Putting all the values in the formula:
Q= (15.0 g) X (0.130 J/g-K) X (310 K-295K)
Q= 29.2 J
Hence, 29.2 J is required to raise the temperature of 15.0 g of lead from 22.0 °C to 37.0 °C.
Learn more about specific heat capacity here:
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