What are the exact solutions of x2 − 3x − 1 = 0 using x equals negative b plus or minus the square root of the quantity b squared minus 4 times a times c all over 2 times a?

Respuesta :

Answer:

The solution of the equation is 3.3 and (-0.3).

Step-by-step explanation:

We need to find the exact solution of the given quadratic equation [tex]x^2-3x-1=0[/tex].

If the quadratic equation is in the form of [tex]ax^2+bx+c=0[/tex], then the solution of this equation is given by :

[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]

On comparing the given equation with this above, it means, a = 1, b = -3 and c = -1.

So,

[tex]x=\dfrac{-(-3)\pm \sqrt{(-3)^2-4\times 1\times (-1)} }{2\times 1}\\\\x=\dfrac{-(-3)+\sqrt{(-3)^{2}-4\times1\times(-1)}}{2\times1}, \dfrac{-(-3)-\sqrt{(-3)^{2}-4\times1\times(-1)}}{2\times1}\\\\x=3.3, -0.30[/tex]

So, the solution of the equation is 3.3 and (-0.3).

Answer:

1

-3

-1

Step-by-step

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