Answer:
x= [tex]2-\sqrt{3}[/tex] and x=[tex]2+\sqrt{3}[/tex]
Step-by-step explanation:
- transfer the -1 to the other side so that the equation reads as [tex]x^{2} -4x+1[/tex]
- factor! think about what numbers add -4 but also multiply to be 1
- you may then realize that there are no numbers with those characteristics
- since that is the case, we have to use the quadratic formula, which is:
[tex]\frac{-b+\sqrt{b^{2}-4ac }}{y}[/tex] and [tex]\frac{-b-\sqrt{b^{2}-4ac }}{y}[/tex]
- the equation is shown as [tex]a^{2}+b^{2}=c^{2}[/tex]
- using the numbers that correspond with those lettered values, plug it in the quadratic formulas
