Answer:
1 mole Of Helium = Weight of Helium/4Weight of Helium = 1*4 = 4 grams 1 mole of Helium contains 6.023*10²³ ( Avogadro number) atoms. Number of moles of in 4 grams of Hydrogen 4 grams is = given weight / molecular weight of Hydrogen (H₂) = 4/2 =2 Number of atoms/molecules in 2 moles of Hydrogen is (2*6.023*10²³) atoms. = 12.046*10²³ atoms.
(Hope this helps)
The number of atoms in 2 moles of helium is 1.204×10²⁴ atoms
From Avogadro's hypothesis,
1 mole of any substance = 6.02×10²³ atoms
Thus,
1 mole of helium = 6.02×10²³ atoms
With the above information in mind, we can obtain the number of atoms in 2 moles of helium as follow:
1 mole of helium = 6.02×10²³ atoms
Therefore,
2 moles of helium = 2 × 6.02×10²³ atoms
2 moles of helium = 1.204×10²⁴ atoms
Thus, we can conclude that 2 moles of helium contains 1.204×10²⁴ atoms
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