Question

How many Liters are in 17.3 moles of Iron?

Answer 1

Answer:

There are 0.12269 Liters of Iron

Explanation:

First, by means of the molecular weight equation, the grams of iron corresponding to 17.3 moles can be calculated:

$MW=\frac{mass(grams)}{moles}$

$mass=MW*moles=55.845\frac{g}{mol} *17.3mol=966.119 g$

Then using the density equation the iron milliters are calculated:

$d=\frac{mass(g)}{volume(mL)}$

$volume=\frac{mass}{density}=\frac{966.119g}{7.874\frac{g}{mL} } =122.69 mL$

Milliliters to liters are converted:

122.69 mL = 0.12269 L of Iron.

Answer 2

Answer:

$V_{Fe}=0.125L$

Explanation:

Hello,

In this case, given the moles of iron, we need to use it atomic mass (55.845  g/mol) and density (7.874 g/cm³) in order to firstly convert from moles to grams and secondly from grams to cubic centimetres:

$V_{Fe}=17.6molFe\times \frac{55.845gFe}{1molFe}*\frac{1cm^3}{7.874gFe}=124.8cm^3$

Finally, we obtain the volume in litres by:

$V_{Fe}=124.8cm^3*\frac{1L}{1000cm^3} \\\\V_{Fe}=0.125L$

Best regards.