Answer:
The solutions of the above equation are -2.26 and 1.75.
Step-by-step explanation:
Given quadratic equation is [tex]h(t) = -9.8t^2-5t + 39[/tex]. It is required to find the solutions of this quadratic equation.
The general form of quadratic equation is given by :
[tex]ax^2+bx+c=0[/tex]
The solution of equation is :
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]
On comparing the given equation,
a = -9.8, b = -5 and c = 39
Its solutions are :
[tex]t=\dfrac{-(-5)+ \sqrt{(-5)^2-4\times (-9.8)(39)} }{2\times (-9.8)}, \dfrac{-b- \sqrt{b^2-4ac} }{2a}\\\\t=-2.26, 1.75[/tex]
So, the solutions of the above equation are -2.26 and 1.75.
