Let x represent number of rabbits and y represent number of chickens.
We have been given that Jessie told her friends that there were total 30 heads for both animals. This means that there are total 30 animals.
[tex]x+y=30...(1)[/tex]
[tex]y=30-x...(1)[/tex]
We have been given that Jessie only had chicken and rabbits. We know that a rabbit has 4 legs, so total number of legs for x rabbits would be [tex]4x[/tex].
We know that a chicken has 2 legs, so total legs of y chickens would be [tex]2y[/tex].
Since all animals has 76 legs in all, so we can represent this information in an equation as:
[tex]4x+2y=76...(2)[/tex]
Upon substituting equation (1) in equation(2), we will get:
[tex]4x+60-2x=76[/tex]
[tex]2x+60=76[/tex]
[tex]2x+60-60=76-60[/tex]
[tex]2x=16[/tex]
[tex]\frac{2x}{2}=\frac{16}{2}[/tex]
[tex]x=8[/tex]
Therefore, Jessie have 8 rabbits on his farm.
Number of chickens would be [tex]y=30-x\Rightarrow 30-8=22[/tex].
Therefore, Jessie have 22 chickens on his farm.