Question

Find the third, fifth, and eleventh terms of the sequence described by the rule.
A(n) = 13+ (n - 1)(5)
A(3)= (Simplify your answer. Type an integer or a decimal.)​

Answer 1

Answer:

Third term is 23

Fifth term is 33

Eleventh term is 63

Step-by-step explanation:

It is given sequence is $A(n)=13+(n-1)5$

We have to find the third,fifth and eleventh term of the sequence.

For third term put n=3 in sequence.

$A(3)=13+(3-1)5$

$=23$

Therefore 3 term is 23

For fifth term put n = 5

$A(5)=13+(5-1)5$

=33

Therefore fifth term is 33

For eleventh term put n = 11

$A(11)=13+(11-1)5$

=63