The radius of a circle is 6mm. What is the area of the shaded portion of the circle.
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The area of the shaded portion of the circle is [tex]\frac{29\pi}{3} \ mm^{2}[/tex]. The correct option is b) 29 π mm² got to station 3
From the question, we are to determine the area of the shaded portion.
The shaded portion in the circle is the major sector.
The area of a sector is given by the formula,
[tex]A = \frac{\theta}{360 ^\circ} \times 2\pi r[/tex]
Where [tex]\theta[/tex] is the angle subtended by the sector
and r is the radius of the circle.
From the given information,
r = 6 mm
and [tex]\theta[/tex] is the angle subtended by the major sector
Therefore
[tex]\theta = 360^\circ - 70^\circ[/tex]
[tex]\theta = 290^\circ[/tex]
Putting the parameters into the formula, we get
[tex]A = \frac{290^\circ}{360 ^\circ} \times 2\pi \times 6[/tex]
Simplifying
[tex]A = \frac{29}{3} \tim\pi \ mm^{2}[/tex]
Hence, the area of the shaded portion of the circle is [tex]\frac{29\pi}{3} \ mm^{2}[/tex]. The correct option is b) 29 π mm² got to station 3
Lear more on area of a sector here: https://brainly.com/question/10090807