Respuesta :
Answer:
We conclude that the Escalade buyers are younger on average than the typical Cadillac buyer.
Step-by-step explanation:
We are given that the average Cadillac buyer is older than 60, past the prime middle years that typically are associated with more spending.
A sample of 50 Escalade purchasers has average age 45 (with standard deviation 25).
Let [tex]\mu[/tex] = average age of an Escalade buyers.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] [tex]\geq[/tex] 60 {means that the Escalade buyers are are of equal age or older on average than the typical Cadillac buyer}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 60 {means that the Escalade buyers are younger on average than the typical Cadillac buyer}
The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;
T.S. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean age of Escalade purchasers = 45
s = sample standard deviation = 25
n = sample of Escalade purchasers = 50
So, the test statistics = [tex]\frac{45-60}{\frac{25}{\sqrt{50} } }[/tex] ~ [tex]t_4_9[/tex]
= -4.243
The value of t test statistics is -4.243.
Now, at 0.05 significance level the t table gives critical value of -1.677 at 49 degree of freedom for left-tailed test.
Since our test statistic is less than the critical value of t as -4.243 < -1.677, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.
Therefore, we conclude that the Escalade buyers are younger on average than the typical Cadillac buyer.