Question

You throw a ball up in the air.the basketball's height,in feet,is given by the function:h=-16t^2+30t+4,where t is the time in seconds after the ball leaves your hand.Find the greatest height the ball reaches(use a calculator).​

Answer 1

Answer:

18.0625 ft

Step-by-step explanation:

Greatest height is when:

t = -b/2a

t = -30/2(-16)

t = 15/16

Greatest height is:

-16t(15/16)² + 30(15/16) + 4 = 289/16

= 18.0625m