Question

find the two values that x can have if x2-12=37​

Answer 1

Answer:

$x2 - 12 = 37$

Step-by-step explanation:

Add 12 to both sides:

$x2 - 12 + 12 = 37 + 12$

Simpilfy:

$x2 = 49$

Simplify:

$2x^{2} = 49$

Simplify:

$\frac{2x^{2} }{2} = \frac{49}{2}$

$x^{2} = \frac{49}{2}$

For x^2 = f(a) the solutions are x = $\sqrt{f(a)} , - \sqrt{f(a)}$

x = $\sqrt{\frac{49}{2} } , x = -\sqrt{\frac{49}{2} }$

-$\sqrt{\frac{49}{2} } = -\frac{7\sqrt{2} }{2}$

x = $\frac{7\sqrt{2} }{2} , x = -\frac{7\sqrt{2} }{2}$

Hope I helped, may I get brainliest and a thanks?

Thank you, have a good day! =)

Answer 2

Answer:

$x = 7 \\ x = - 7$

Step-by-step explanation:

${x}^{2} - 12 = 37 \\ {x}^{2} = 37 + 12 \\ {x}^{2} = 49 \\ x = \sqrt{49} \\ x = 7 \\ x = - 7$