Answer:
The potential difference is 224V .
Explanation:
Given that the formula of power is P = I×V and formula of voltage is V = I×R where both I represents current.
Given that the formula of power is P = I×V and formula of voltage is V = I×R where both I represents current. Then you have to use voltage formula to make I the subject :
[tex]v = i \times r[/tex]
[tex]i = \frac{v}{r} [/tex]
So that you can substitute it into the formula of power :
[tex]p = i \times v[/tex]
[tex]p = \frac{v}{r} \times v[/tex]
[tex]p = \frac{ {v}^{2} }{r} [/tex]
Let p = 500W,
Let r = 100Ω,
[tex]500 = \frac{ {v}^{2} }{100} [/tex]
[tex]500 \times 100 = {v}^{2} [/tex]
[tex] {v}^{2} = 50 \: 000[/tex]
[tex]v = \sqrt{50000} [/tex]
[tex]v = 224 \: \: (3s.f)[/tex]
