There are 3 ways of solving a simultaneous problem, substitution method, elimination method and Gauss-Jordan method. I'm gonna use the substitution method since it's easier and i think it would suit your level more.
First let's try solving for y since it's easier to start with.
Firstly we have to find an equation for x:
[tex]x-2y=2\\x-2y+2y=2+2y\\x=2+2y[/tex]
Great, now we can use the substitution method to find the value of y using the first equation:
[tex]2x+3y=11\\2(2+2y)+3y=11\\4+4y+3y=11\\7y=7\\y=1[/tex]
Now we know that y=1 we can solve the first equation we made:
[tex]x=2+2y\\x=2+2(1)\\x=4[/tex]
And the answer is [tex]x=4 , y= 1\\(4,1)[/tex]
Double check:
[tex]2x+3y=11\\2(4)+3(1)=11\\8+3=11\\11=11\\\\x-2y=2\\(4)-2(1)=2\\2=2[/tex]
And that's our final answer! (4,1)
