Respuesta :

Answer:a

Step-by-step explanation:

Given

[tex]f(x)=1.6^x\sin 3x[/tex]

we know that value of sin function vary between [tex]-1\ \text{to}\ 1[/tex]

i.e. it take finite value so

[tex]\lim \limits_{x\rightarrow -\infty}f(x)=\lim \limits_{x\rightarrow -\infty}\quad 1.6^x\sin 3x[/tex]

when [tex]x\rightarrow -\infty[/tex]

then [tex]1.6^x\rightarrow 0[/tex]

therefore

[tex]\lim \limits_{x\rightarrow -\infty}\quad 1.6^x\sin 3x=0[/tex]

option a is correct