Answer:
log(0.4444^(-12))
Step-by-step explanation:
To find when the car will worth $10,000, we just need to use the value of V = 10000 and then find the value of t:
10000 = 22500 * 10^(-t/12)
10^(-t/12) = 0.4444
log(10^(-t/12)) = log(0.4444)
(-t/12)*log(10) = log(0.4444)
-t/12 = log(0.4444)
t = -12 * log(0.4444) = log(0.4444^(-12))
As the answer needs to be expressed as a base 10 logarithm, we have that the car will worth $10,000 when t = log(0.4444^(-12)) years
