Question

If a polynomial function f(x) has roots 0, 3, and 2+ V5, what must also be a root of f(x)?
-2-sqrt15
2-sqrt15
15-sqrt 2
15+sqrt 2

Answer 1

Answer:

Option B.

Step-by-step explanation:

Note: Given roots are not in proper format.

Consider the polynomial function f(x) has roots 0, 3, and $2+\sqrt{15}$.

According to irrational root theorem if $a+\sqrt{b}$ is root of a polynomial P(x), then $a-\sqrt{b}$ is also a root of polynomial P(x).

Since $2+\sqrt{15}$ is an irrational root of the function f(x). By irrational root theorem $2-\sqrt{15}$ is also a root of function f(x).

Therefore, the correct option is B.

Answer 2

Answer:

B)

Step-by-step explanation: