Question

How many liters of CO2 form at STP if 5.0 g of
CaCO3 are treated with excess hydrochloric acid?

Answer 1

Answer: STP

CaCO3 = 5 g

Convert gram to mol

100 g of CaCO3   = 1 mol

5 g of  CaCO3 (n)  = 5 g *(1 mol/100 g) = 0.05 mol

Gas law  

PV =nRT

V = nRT/P  

V = (0.05 mol * (0.08206 L atm /K mol) *273 K)/1 atm

V = 1.124 L

Explanation: