Question

The area of a rectangle is given by A(x) = x2 + 5x with x being the height and x + 5 being the base. If the area is 14, what is the only viable solution for the height? Why are there not two solutions?​

Answer 1

Answer:

See below.

Step-by-step explanation:

A(x) = x^2 + 5x

A(x) = x^2 + 5x = 14

x^2 + 5x - 14 = 0

(x + 7)(x - 2) = 0

x + 7 = 0  or  x - 2 = 7

x = -7 or x = 2

x is the height of a rectangle.

The only viable solution is x = 2 because the height of a rectangle cannot be a negative number such as -7.

Answer 2

The only viable solution for the height is x= 2, because height cannot be a negative value.

What  is Rectangle?

A rectangle is a quadrilateral with four right angles.

What is Area?

Area is the quantity that expresses the extent of a region on the plane or on a curved surface.

What is Quadratic equation?

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is $ax^{2} +bx+c=0$

Given,

Area of the rectangle = $x^{2} +5x$ = 14

Then,

$x^{2} +5x-14=0\\(x+7)(x-2)=0$

Therefore x = -7 and 2

But the Height cannot be negative therefore x = 2

Hence, only viable solution for the height is x= 2, because height cannot be a negative value.

Learn more about Rectangle, Area and Quadratic equation here

https://brainly.com/question/12555839

#SPJ2