Question

What is the temperature of an ideal gas if 2.50
moles of the gas occupy a 3.00 liter container
at a pressure of 2500. kPa? Record your answer
to the nearest Kelvin.
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Answer 1

Answer: The temperature of an ideal gas is 360 K

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 2500 kPa = 24.67 atm   (1kPa= 0.0098atm)

V = Volume of gas = 3.00 L

n = number of moles = 2.50 mol

R = gas constant =$0.0821Latm/Kmol$

T = temperature = ?

$T=\frac{PV}{nR}$

$T=\frac{24.67atm\times 3.00L}{0.0821 L atm/K mol\times 2.50mol}=360K$

Thus the temperature of an ideal gas if 2.50 moles of the gas occupy a 3.00 liter container is 360 K