Solve the following problem:
Given: △SAL, SA = LA
AT − ∠bisector
Prove: m∠L = m∠S
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Answer:
[tex]\angle L=\angle S[/tex] using congruence rule
Step-by-step explanation:
Given: ΔSAL, SA = LA and AT is the bisector of [tex]\angle A[/tex]
To prove: [tex]\angle L=\angle S[/tex]
Proof:
Two triangles are congruent if they have same shape and same size.
Consider triangles ALT and AST
AL = AS
As AT bisects [tex]\angle A[/tex], [tex]\angle LAT=\angle SAT\\[/tex]
AT = AT (common side)
So, [tex]\Delta ALT\cong \Delta AST[/tex] ( by SAS congruence rule )
Here, SAS denotes side-angle-side
[tex]\angle L=\angle S[/tex] (using corresponding parts of congruent triangles)
Hence proved
Explanation:
First, we know that △ALT ≅ △AST, because of Side Angle Side Theorem. Next, we know that AL ≅ AS, because it's given.
Since A = A, we can remove A and it gives us m∠L = m∠S.
If you need to show work in math terms, your answer should look something like this:
1. △ ALT ≅ △AST - SAS
2. AL ≅ AS - Given
3. m∠ L ≅ m∠S
Hope this helped!