Given: m arc AB = 6x, m arc BC = 6x, m arc CD= x, m arc DA= 2x
Find: m < ATB
![Given m arc AB 6x m arc BC 6x m arc CD x m arc DA 2x Find m lt ATB class=](https://us-static.z-dn.net/files/d0f/5b30e1a84ca04f6bda9ada96f1168eb3.png)
Answer:
m∠ATB=84°
Step-by-step explanation:
First we have to find the measure of angle ATB in terms of x
The equation would be m∠ATB=1/2(AB+DC)
Subsitute Values and you get m∠ATB=3.5x
The next step is solving for x.
Add all of the values and you get 15x. The arcs should equal 360°. This means 15x=360°
x=24° Plug it in and you get m∠ATB=84°
The measure of m∠ATB is 84 degrees
From the given figure, we have the following parameters
m arc AB = 6x,
m arc BC = 6x,
m arc CD= x,
m arc DA= 2x
Required parameters
m<ATB
The expression to use to get the required angle is m∠ATB=1/2(AB+DC)
Substitute the given parameters
m∠ATB=1/2(AB+DC)
m∠ATB=1/2(6x+ x)
m∠ATB=1/2(7x)
Since x = 24 degrees, hence
m∠ATB=1/2(7*24)
m∠ATB= 84 degrees
Hence the measure of m∠ATB is 84 degrees
Learn more on circle geometry here: https://brainly.com/question/24375372