Question

Given the following equation: Ca(OH)2 + 2HNO3 --> 2 H2O
+ Ca(NO3)2
How many moles of water are produced when 2.27
moles of calcium hydroxide reacts with excess nitric
acid?
Please include your units and round to two decimal places.

Answer 1

Answer: 4.45 moles of $H_2O$ will be produced.

Explanation:

The balanced chemical equation:

$Ca(OH)_2+2HNO_3\rightarrow 2H_2O+Ca(NO_3)_2$

As nitric acid is the excess reagent, calcium hydroxide is the limiting reagent as it limits the formation of product.

According to stoichiometry :

1 mole of $Ca(OH)_2$ produce = 2 moles of $H_2O$

Thus 2.27moles of $Ca(OH)_2$ will produce =$\frac{2}{1}\times 2.27=4.54moles$  of $H_2O$

Thus 4.45 moles of $H_2O$ will be produced.