Given: circle k(O)
m∠WVX = 51°
m arc WV = 135°
Find: m arc XV
![Given circle kO mWVX 51 m arc WV 135 Find m arc XV class=](https://us-static.z-dn.net/files/d29/0e42d303c520b92b161c945ec533e8d9.png)
Answer:
123°
Step-by-step explanation:
The following property must be satisfied
m∠WVX = m arc WX / 2
m arc WX = 2*m∠WVX
m arc WX = 2*51°
m arc WX = 102°
The summation of the three arcs that compound the circle is equal to 360°
m arc WX + m arc XV + m arc WV = 360°
m arc XV = 360° - m arc WV - m arc WX
m arc XV = 360° - 135° - 102°
m arc XV = 123°
Answer:
123 degrees
Step-by-step explanation:
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