Answer:
Anna's number could be 5 and it could be 6.
Step-by-step explanation:
Let Anna's number be represented by x.
If Bill squared her number followed by subtracting 11 times her number, and adding 4, then he would get -26.
This implies that:
[tex]x^2 - 11x + 4 = -26[/tex]
This is a quadratic equation and we can solve for x by factorization.
[tex]x^2 - 11x + 4 = -26\\\\=> x^2 - 11x + 4 + 26 = 0\\\\x^2 - 11x + 30 = 0\\\\x^2 -6x-5x + 30 = 0\\\\x(x - 6) - 5(x - 6) = 0\\\\(x - 5) (x - 6) = 0\\\\[/tex]
=> x = 5 and x = 6
Anna's number could be 5 and it could be 6.